Question

\(\dfrac{2}{3x}-\dfrac{5\left(x-4\right)-43}{2}=\dfrac{65}{6}\)

 giải x

Answer 1

đk : x khác 0 

ta có :

\(pttđ:\dfrac{2.2}{3x.2}-\dfrac{5x-20-43}{2}=\dfrac{65}{6}\)

\(\Leftrightarrow\dfrac{4}{6x}-\dfrac{\left(5x-63\right).3.x}{2.3.x}=\dfrac{65x}{6x}\)

\(\Leftrightarrow\dfrac{4}{6x}-\dfrac{3x\left(5x-63\right)}{6x}=\dfrac{65x}{6x}\)

\(\Leftrightarrow\dfrac{4}{6x}-\dfrac{15x^2-189x}{6x}=\dfrac{65x}{6x}\)

\(\Leftrightarrow4-15x^2-189x-65x=0\)

\(\Leftrightarrow-15x^2+4-254=0\)

\(\Delta=\left(4\right)^2-4.-15.-254=-15224\)

vì \(\Delta< 0\)

=> pt vô nghiệm