\(\dfrac{2}{3}\sqrt{9u-9}-\dfrac{1}{4}\sqrt{16u-16}+27\sqrt{\dfrac{u-1}{81}}=4\left(dk:u\ge1\right)\)
\(\Leftrightarrow\dfrac{2}{3}\sqrt{9\left(u-1\right)}-\dfrac{1}{4}\sqrt{16\left(u-1\right)}+27\dfrac{\sqrt{u-1}}{\sqrt{81}}=4\)
\(\Leftrightarrow2\sqrt{u-1}-\sqrt{u-1}+3\sqrt{u-1}=4\\ \Leftrightarrow\sqrt{u-1}.\left(2-1+3\right)=4\\ \Leftrightarrow4\sqrt{u-1}=4\\ \Leftrightarrow\sqrt{u-1}=1\\ \Leftrightarrow u-1=1\\ \Leftrightarrow u=2\left(tm\right)\)
Vậy \(S=\left\{2\right\}\)