Question

\(\dfrac{2^{2x-3}}{4^{10}}=8^3.16^5\)

Answer 1

`=> 2^(2x-3) = 2^6 xx 2^20 xx 2^20`

`=> 2^(2x-3) = 2^46`

`=> 2x - 3 = 46`

`=> x = 49/2`

Answer 2

\(\dfrac{2^{2x-3}}{4^{10}}=8^3.16^5\\ =>2^{2x-3}=8^3.16^5.4^{10}=\left(2^3\right)^3.\left(2^4\right)^5.\left(2^2\right)^{10}=2^{3.3}.2^{4.5}.2^{2.10}\\ =>2^{2x-3}=2^9.2^{20}.2^{20}=2^{9+20+20}=2^{49}\\ =>2x-3=49\\ =>2x=52\\ =>x=26\)

Answer 3

\(\dfrac{2^{2x-3}}{4^{10}}=8^3.16^5\)

\(2^{2x-3}=8^3.16^5.4^{10}\)

\(2^{2x-3}=\left(2^3\right)^3.\left(2^4\right)^5.\left(2^2\right)^{10}\)

\(2^{2x-3}=2^9.2^{20}.2^{20}\)

\(2^{2x-3}=2^{49}\)

\(\Rightarrow2x-3=49\)

\(2x=49+3\)

\(2x=52\)

\(x=\dfrac{52}{2}\)

\(x=26\)

Vậy \(x=26\)