\(\dfrac{20}{50}\times\dfrac{150}{120}=\dfrac{3000}{6000}=\dfrac{1}{2}\)
\(\dfrac{20}{50}\) x \(\dfrac{150}{120}=\dfrac{3000}{6000}=\dfrac{1}{2}\)
150-(\(\dfrac{2}{5}\)+\(\dfrac{50}{5}\))=...
\(\dfrac{5}{2}\) bằng :
a. \(\dfrac{25}{10}\) b. \(\dfrac{50}{20}\) c. \(\dfrac{15}{6}\) d. \(\dfrac{20}{8}\)
chọn cái nào h :)?
\(\dfrac{120}{20}\)
tính thuận tiện
\(\dfrac{3}{7}\) x \(\dfrac{9}{20}\) + \(\dfrac{11}{7}\) x \(\dfrac{9}{20}\)
Tìm x, biết:
a) x - 2 = \(\dfrac{7}{15}\)
b) \(\dfrac{9}{20}\) + x = \(\dfrac{2}{5}\) + \(\dfrac{3}{20}\)
tính bằng cách thuận tiện nhất
\(\dfrac{17}{20}x\dfrac{27}{13}+\dfrac{27}{13}x\dfrac{3}{20}\)
tìm x a, \(\dfrac{x}{4}\) =\(\dfrac{15}{20}\) b, \(\dfrac{15}{x}\) = \(\dfrac{25}{35}\) c, \(\dfrac{x}{5}\)=\(\dfrac{26}{65}\) d, \(\dfrac{3}{x}\)=\(\dfrac{51}{85}\)
\(x+\dfrac{3}{7}=\dfrac{35}{50}\)
Y x \(\dfrac{1}{2}\) + Y x \(\dfrac{1}{6}\) + Y x \(\dfrac{1}{12}\) + Y x \(\dfrac{1}{20}\) = \(\dfrac{8}{5}\)
\(\dfrac{19}{20}-x=\dfrac{17}{20}\)
