Question

\(\dfrac{2011\cdot2022+2023\cdot11\cdot2011}{2021\cdot2022-2022\cdot2020}\)
Tính nhanh

Answer 1

`A=(2011xx2022+2023xx11xx2011)/(2021xx2022-2022xx2020)`

`A=(2021xx2022+(2022+1)xx11+2011)/(2022xx(2021-2020))`

`A=(2021xx2022+2022xx11+11+2011)/2022xx1`

`A=(2021xx2022+2022xx11+2022)/2022`

`A=(2022xx(2011+11+1))/2022`

`A=(2022xx2023)/2022`

`A=2023/1`

`=>A=2023`

Answer 2

hếp mê