Question

\(\dfrac{1}{6}-\left(\dfrac{2}{3}\right)^2+\dfrac{5}{18}\)

Answer 1

\(\dfrac{1}{6}-\left(\dfrac{2}{3}\right)^2+\dfrac{5}{18}=\dfrac{1}{6}-\dfrac{4}{9}+\dfrac{5}{18}=\dfrac{3}{18}-\dfrac{8}{18}+\dfrac{5}{18}=0\)

Answer 2

\(\dfrac{1}{6}-\left(\dfrac{2}{3}\right)^2+\dfrac{5}{18}\Leftrightarrow\dfrac{1}{6}-\dfrac{4}{9}+\dfrac{5}{18}\Leftrightarrow\dfrac{3-8+5}{18}=\dfrac{0}{18}=0\)

Answer 3

= 0 e nhé