theo đề ta có \(\dfrac{x}{5}-x+\dfrac{1}{5}=\dfrac{3}{4}\)
\(\Leftrightarrow\dfrac{x}{5}-\dfrac{5x}{5}+\dfrac{1}{5}=\dfrac{3}{4}\)
\(\Leftrightarrow\dfrac{1-4x}{5}=\dfrac{3}{4}\)
\(pt\Leftrightarrow4\left(1-4x\right)=15\)
\(4-16x=15\)
\(-16x=15-4=11\)
x=\(-\dfrac{11}{16}\)