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Hoàng Gia Bảo số 11

\(\dfrac{1}{21}+\dfrac{1}{28}+\dfrac{1}{36}+...+\dfrac{2}{x\left(x+1\right)}=\dfrac{2}{9}\)

dương phúc thái
6 tháng 5 2023 lúc 17:11

\(\dfrac{1}{3.7}\)+\(\dfrac{1}{7.4}\) +\(\dfrac{1}{4.9}\) +...+\(\dfrac{2}{x\left(x+1\right)}\) =\(\dfrac{2}{9}\) 

\(\dfrac{2}{2.3.7}\)+\(\dfrac{2}{2.7.4}\) +\(\dfrac{2}{2.4.9}\) +...+\(\dfrac{2}{x\left(x+1\right)}\) =\(\dfrac{2}{9}\) 

\(\dfrac{2}{6.7}\)+\(\dfrac{2}{7.8}\) +\(\dfrac{2}{8.9}\) +...+\(\dfrac{2}{x\left(x+1\right)}\) =\(\dfrac{2}{9}\) 

2(\(\dfrac{1}{6.7}\) +\(\dfrac{1}{7.8}\) +\(\dfrac{1}{8.9}\) +...+\(\dfrac{1}{x\left(x+1\right)}\)) =\(\dfrac{2}{9}\) 

2(\(\dfrac{1}{6}\) -\(\dfrac{1}{7}\) +\(\dfrac{1}{7}\) -\(\dfrac{1}{8}\) +\(\dfrac{1}{8}\) -\(\dfrac{1}{9}\) +...+\(\dfrac{1}{x}\)-\(\dfrac{1}{x+1}\) ) =\(\dfrac{2}{9}\) 

2(\(\dfrac{1}{6}\) -\(\dfrac{1}{x+1}\) )=\(\dfrac{2}{9}\) 

\(\dfrac{1}{6}\)-\(\dfrac{1}{x+1}\) =\(\dfrac{2}{9}\) : 2

\(\dfrac{1}{6}\)-\(\dfrac{1}{x+1}\) =\(\dfrac{1}{9}\) 

\(\dfrac{1}{x+1}\) = \(\dfrac{1}{6}\) -\(\dfrac{1}{9}\) 

\(\dfrac{1}{x+1}\) = \(\dfrac{1}{18}\) 

x+1=18

x    = 18-1

x    =17

Vậy x =17