Question

\(\dfrac{10}{2}+\dfrac{x}{f}=\dfrac{5}{6}-\dfrac{1}{3}\)

Vậy x/f = ????

Answer 1

`10/2+x/f=5/6-1/3`

`=>10/2+x/f=1/2`

`=>x/f=1/2-10/2`

`=>x/f=-9/2`

Answer 2

=> 

\(\dfrac{x}{f}=\left(\dfrac{5}{6}-\dfrac{1}{3}\right)-\dfrac{10}{2}=\dfrac{-9}{2}\)

Answer 3

10/2 + x/f = 5/6 - 2/6

10/2 + x/f = 3/6 = 1/2

           x/f = 1/2 - 10/2

           x/f = -9/2

Vậy...

Answer 4

`10/2 + x/f = 5/6 - 2/6`

`=>10/2 + x/f = 3/6 = 1/2`

`=>  x/f = 1/2 - 10/2`

`=>x/f = -9/2`