Lời giải:
\(\frac{10^2+11^2+12^2}{13^2+14^2}=\frac{365}{365}=1\)
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dfrac{1}{5}+dfrac{2}{11} dfrac{x}{55} dfrac{2}{5}+dfrac{1}{5} dfrac{1}{2}+dfrac{1}{3}+dfrac{1}{6} xledfrac{13}{4}+dfrac{14}{8} dfrac{1}{4}+dfrac{5}{12}+dfrac{-1}{13} x dfrac{7}{5}+dfrac{2}{10}+dfrac{1}{2} dfrac{79}{15}+dfrac{7}{5}+dfrac{-8}{3}le xledfrac{10}{3}+dfrac{15}{4}+dfrac{23}{12}
Đọc tiếp
\(\dfrac{1}{5}+\dfrac{2}{11}< \dfrac{x}{55}< \dfrac{2}{5}+\dfrac{1}{5}\) \(\dfrac{1}{2}+\dfrac{1}{3}+\dfrac{1}{6}< x\le\dfrac{13}{4}+\dfrac{14}{8}\)
\(\dfrac{1}{4}+\dfrac{5}{12}+\dfrac{-1}{13}< x< \dfrac{7}{5}+\dfrac{2}{10}+\dfrac{1}{2}\) \(\dfrac{79}{15}+\dfrac{7}{5}+\dfrac{-8}{3}\le x\le\dfrac{10}{3}+\dfrac{15}{4}+\dfrac{23}{12}\)
28 tháng 4 2021 lúc 19:51
Cho S= \(\dfrac{3}{10}+\dfrac{3}{11}+\dfrac{3}{12}+\dfrac{3}{13}+\dfrac{3}{14}\)
Chứng minh rằng: 1<S<2
(10^2+11^2+12^2):(13^2+14^2)
(10^2+11^2+12^2):(13^2+14^2)
(10^2+11^2+12^2) : (13^2+14^2)
10^2+11^2+12^2/13^2+14^2
(10^2 + 11^2 + 12^2) - (13^2 + 14^2) = ?
Bài 1.( 2 điểm)Tính bằng cách hợp lí:a) dfrac{1}{2}+dfrac{9}{10}+dfrac{5}{6}-dfrac{11}{14}-dfrac{1}{3}+dfrac{-4}{35}b) left(dfrac{18}{23}+dfrac{7}{12}right)+left(dfrac{-13}{19}-dfrac{3}{4}right)+left(dfrac{-6}{19}+dfrac{5}{23}right)c) dfrac{4}{3}+dfrac{-5}{6}+dfrac{-1}{4}d) dfrac{5}{6}-dfrac{7}{5}+dfrac{17}{30}
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Bài 1.( 2 điểm)Tính bằng cách hợp lí:
a) \(\dfrac{1}{2}+\dfrac{9}{10}+\dfrac{5}{6}-\dfrac{11}{14}-\dfrac{1}{3}+\dfrac{-4}{35}\)
b) \(\left(\dfrac{18}{23}+\dfrac{7}{12}\right)+\left(\dfrac{-13}{19}-\dfrac{3}{4}\right)+\left(\dfrac{-6}{19}+\dfrac{5}{23}\right)\)
c) \(\dfrac{4}{3}+\dfrac{-5}{6}+\dfrac{-1}{4}\)
d) \(\dfrac{5}{6}-\dfrac{7}{5}+\dfrac{17}{30}\)
Thực hiện phép tính (tính hợp lý nếu có thể): a) dfrac{5}{9}.dfrac{7}{13}+dfrac{5}{9}.dfrac{8}{13}-dfrac{5}{13}.dfrac{2}{9} b) 12dfrac{5}{14}-left(3dfrac{5}{7}+5dfrac{5}{14}right) c)dfrac{-2}{5}+dfrac{7}{11}+dfrac{-11}{10}+dfrac{7}{-11} d) dfrac{1}{2}+dfrac{-2}{3}+dfrac{1}{6}+dfrac{-2}{5}
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Thực hiện phép tính (tính hợp lý nếu có thể):
a) \(\dfrac{5}{9}.\dfrac{7}{13}+\dfrac{5}{9}.\dfrac{8}{13}-\dfrac{5}{13}.\dfrac{2}{9}\) b) \(12\dfrac{5}{14}-\left(3\dfrac{5}{7}+5\dfrac{5}{14}\right)\)
c)\(\dfrac{-2}{5}+\dfrac{7}{11}+\dfrac{-11}{10}+\dfrac{7}{-11}\) d) \(\dfrac{1}{2}+\dfrac{-2}{3}+\dfrac{1}{6}+\dfrac{-2}{5}\)