Question

\(\dfrac{-4}{5}.\dfrac{11}{13}+\dfrac{4}{5}.\dfrac{-2}{13}-\dfrac{1}{5}\)

Answer 1

\(=\dfrac{4}{5}\left(-\dfrac{11}{13}-\dfrac{2}{13}\right)-\dfrac{1}{5}\\ =\dfrac{4}{5}.\left(-\dfrac{13}{13}\right)-\dfrac{1}{5}\\ =\dfrac{-4}{5}-\dfrac{1}{5}=\dfrac{-5}{5}=-1\)

Answer 2

\(-\dfrac{4}{5}.\dfrac{11}{13}+\dfrac{4}{5}.\dfrac{-2}{13}-\dfrac{1}{5}\)

\(=\dfrac{4}{5}.\dfrac{-11}{13}+\dfrac{4}{5}.\dfrac{-2}{13}-\dfrac{1}{5}\)

\(=\dfrac{4}{5}.\left(-\dfrac{11}{13}+\dfrac{-2}{13}\right)-\dfrac{1}{5}\)

\(=\dfrac{4}{5}.\left(\dfrac{-11-2}{13}\right)-\dfrac{1}{5}\)

\(=\dfrac{4}{5}.\left(-\dfrac{13}{13}\right)-\dfrac{1}{5}\)

\(=\dfrac{4}{5}.\left(-1\right)-\dfrac{1}{5}\)

\(=\dfrac{-4}{5}-\dfrac{1}{5}\)

\(=\dfrac{-4-1}{5}\)

\(=-\dfrac{5}{5}\)

\(=-1\)