\(\dfrac{5}{8}\left(-\dfrac{2}{5}+\dfrac{3}{5}\right)=\dfrac{5}{8}\times\dfrac{1}{5}=\dfrac{1}{8}\)
\(\dfrac{5}{8}.\left[\left(\dfrac{-2}{5}\right)+\dfrac{3}{5}\right]\)
= \(\dfrac{5}{8}.\dfrac{1}{5}\)
= \(\dfrac{1}{8}.\dfrac{1}{1}\)
= \(\dfrac{1}{8}\)