Question

\(\dfrac{-18}{42}\)x\(\dfrac{35}{42}\):\(\dfrac{-98}{42}\)

Answer 1

\(-\dfrac{18}{42}\cdot\dfrac{35}{42}:\dfrac{-98}{42}\)

\(=-\dfrac{18}{42}\cdot\dfrac{35}{42}\cdot\dfrac{42}{-98}\)

\(=\dfrac{-18}{42}\cdot\dfrac{-5}{14}\\ =\dfrac{15}{98}\)

Answer 2

\(\dfrac{-18}{42}.\dfrac{3\text{5}}{42}:\dfrac{-98}{42}\)

\(=\dfrac{-18}{42}.\dfrac{3\text{5}}{42}.\dfrac{-42}{98}\)

\(=\dfrac{1\text{5}}{98}\)