Question

\(\dfrac{-11}{31}\cdot\dfrac{-2}{17}+\dfrac{7}{31}\cdot\dfrac{-20}{17}-\dfrac{9}{17}\cdot\dfrac{11}{31}\)

Answer 1

=\(\dfrac{11}{31}\)*\(\left(\dfrac{-2}{17}-\dfrac{-9}{17}\right)\)+\(\dfrac{7}{31}\)*\(\dfrac{-20}{17}\)

=\(\dfrac{11}{31}\)*\(\dfrac{-7}{17}\)+\(\dfrac{7}{31}\)*\(\dfrac{-20}{17}\)

=\(\dfrac{-77}{512}\)+\(\dfrac{-140}{512}\)

=\(\dfrac{-217}{512}\)

Answer 2

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