n/n-3 có giá trị nguyên khi
\(n⋮n-3\)
n-3+3 chia hết cho n-3
3 chia hết cho n-3
n-3=1;-1;3;-3
n=4;2;6;0
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Cho A=n+3/n+2 voi n€z
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