a) \(3\frac{2}{7}=\frac{3.7+2}{7}=\frac{23}{7}\) b) \(2\frac{5}{12}=\frac{2.12+5}{12}=\frac{29}{12}\)
c) \(9\frac{5}{9}=\frac{9.9+5}{9}=\frac{86}{9}\) d) \(12\frac{3}{4}=\frac{12.4+3}{4}=\frac{51}{4}\)
a . \(3\frac{2}{7}=\frac{3\cdot7+2}{7}=\frac{23}{7}\)
b . \(2\frac{5}{12}=\frac{2\cdot12+5}{12}\frac{29}{12}\)
c . \(9\frac{5}{9}=\frac{9\cdot9+5}{9}=\frac{86}{9}\)
d . \(12\frac{3}{4}=\frac{12\cdot4+3}{4}=\frac{51}{4}\)
a, \(3\frac{2}{7}=\frac{3X7+2}{7}=\frac{23}{7}\)
b, \(2\frac{5}{12}=\frac{2X12+5}{12}=\frac{29}{12}\)
c, \(9\frac{5}{9}=\frac{9X9+5}{9}=\frac{86}{9}\)
d, \(12\frac{3}{4}=\frac{12X4+3}{4}=\frac{51}{4}\)
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