Question

Đề bài : a. 2018x (\(\dfrac{1}{2}\)+ \(\dfrac{1212}{2424}\))=?

B. 15x \(\dfrac{2121}{4343}\)+ 15 x \(\dfrac{222222}{434343}\)

đề hơi khó 🥲

Answer 1

`a)2018xx(1/2+1212/2424)`

`=2018xx(1/2+1/2)`

`=2018xx2/2=2018`

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`b)15xx2121/4343+15xx222222/434343`

`=15xx(2121/4343+222222/434343)`

`=15xx(21/43+22/43)`

`=15xx43/43=15`

Answer 2

a.2018x1=2018

b.15x(21/43+22/43)=15x1=15

Answer 3

A)2018

B)15