( 2.x -1)2 -5 =20
( 2.x -1)2 = 20+5
( 2.x -1)2 =25 = 52
( 2.x -1)2 = 52
=> 2.x -1 =5
2.x = 5+1
2.x =6
=> x = 6:2 =3
=> x =3
li-ke nhé
\(\left(2x-1\right)^2-5=20\)
=> \(\left(2x-1\right)^2=20+5\)
=>\(\left(2x-1\right)^2=25\)
=>\(\left(2x-1\right)^2=5^2=\left(-5\right)^2\)
+) 2x-1=5
=> 2x=5+1
=> 2x=6
=> x=6:2
=> x=3
+) 2x-1=-5
=> 2x=-5+1
=> 2x=-4
=> x=-4:2
=> x=-2
Vậy \(x\in\left\{-2;3\right\}\).