\(\frac{1}{1}=1\)
Viết lại: 1+2+1+2+3+...+1+2+...+10
=2+6+...+55
=163
Hội con 🐄 chúc bạn học tốt!!!
\(D=\frac{1}{1+2}+\frac{1}{1+2+3}+\frac{1}{1+2+3+4}+...+\frac{1}{1+2+3+...+10}\)
\(D=\frac{1}{3}+\frac{1}{6}+\frac{1}{10}+...+\frac{1}{\frac{\left[1+10\right]\cdot10}{2}}\)
\(D=\frac{1}{3}+\frac{1}{6}+\frac{1}{10}+...+\frac{1}{55}\)
\(D=\frac{2}{6}+\frac{2}{12}+\frac{2}{20}+...+\frac{2}{110}\)
\(\frac{D}{2}=2\left[\frac{1}{6}+\frac{1}{12}+\frac{1}{20}+...+\frac{1}{110}\right]\)
\(D=2\left[\frac{1}{2\cdot3}+\frac{1}{3\cdot4}+\frac{1}{4\cdot5}+...+\frac{1}{10\cdot11}\right]\)
\(D=2\left[\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{10}-\frac{1}{11}\right]\)
\(D=2\left[\frac{1}{2}-\frac{1}{11}\right]\)
\(D=\frac{9}{11}\)
Vậy D = 9/11
Bỏ chỗ \(\frac{D}{2}\)nhé Hoa Thiên Cốt
bạn ơi là:
\(\frac{1}{1+2}+\frac{1}{1+2+3}+...\)
ko phải theo cách bn nghĩ đâu
