1+2+3+...+X=500500
=>\(\dfrac{\left(x-1\right)+1\cdot\left(1+x\right)}{2}\)=500500
=>x\(\cdot\)(x+1)=500500x2=1001000=1000x1001
=>x=1000.
Đúng 2
Bình luận (0)
1+2+3+...+X=500500
=>\(\dfrac{\left(x-1\right)+1\cdot\left(1+x\right)}{2}\)=500500
=>x\(\cdot\)(x+1)=500500x2=1001000=1000x1001
=>x=1000.
tìm x
1+2+3+4+...+x=500500
Tìm x , biết:
1+2+3+4+...+x=500500
tìm x biết
a) 1 + 2 + 3 + ...... + x = 500500
b) 2x - 23 . 32 = 138
c) ( 6x - 34 ) . 73 = 3 . 74
d) 125 - 5 ( 3x - 1 ) = 55 : 53
e) 4x+1 + 40 = 65
j) 17 - 2 ( 2x - 3 ) = 3
giúp mk nha mk cần gấp
1+2*3+...+x=500500.Tim x
1+2+3+...+x=500500
1+2+3+......+x=500500
1+2+3+...+x=500500
1+2+3+...+x=500500