\(x^4+4x^2+2014=\left(x^2+2\right)+2000>0\)
=> PT vô nghiệm
Ta có : x4 \(\ge\)0 ; 4x2 \(\ge\)0 ; 2014 > 0
=> x4 + 4x2 + 2014 > 0
=> x4 + 4x2 + 2014 vô nghiệm
\(\left(\left(x^2\right)^2+2x.2+4\right)+2010\)
\(\left(x^2+2\right)^2+2010\ge2010>0\)
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