\(\text{ta thấy }\frac{3}{1^2.2^2}=\frac{1}{1^2}-\frac{1}{2^2};\frac{5}{2^2.3^2}=\frac{1}{2^2}-\frac{1}{3^2};....;\frac{199}{99^2.100^2}=\frac{1}{99^2}-\frac{1}{100^2}\)
\(\text{suy ra }\)\(\frac{3}{1^2.2^2}+\frac{5}{2^2.3^2}+...+\frac{199}{99^2.100^2}=\frac{1}{1^2}-\frac{1}{2^2}+\frac{1}{2^2}-\frac{1}{3^2}+...+\frac{1}{99^2}-\frac{1}{100^2}\)
\(=\frac{1}{1^2}-\frac{1}{100^2}=\frac{1}{1}-\frac{1}{10000}=\frac{10000}{10000}-\frac{1}{10000}=\frac{9999}{10000}
\(\Rightarrow\frac{3}{1.4}+\frac{5}{4.9}+...+\frac{199}{9801.1000}\)
\(\Rightarrow1-\frac{1}{4}+\frac{1}{4}-\frac{1}{9}+...+\frac{1}{9801}-\frac{1}{1000}\)
\(\Rightarrow1-\frac{1}{1000}< 1\)
