Lưu Tuấn Mạnh

CMR:

\(A=2^1+2^2+...+2^{2010}⋮3,7\)

\(B=3^1+3^2+...+3^{2010}⋮4,13\)

A=(2+22)+(23+24)+...+(22009+22010

A=2(1+2)+23(1+2)+...+22009(1+2) 

A=2.3+23.3+...+22009.3

A=3(2+23+...+22009) chia hết cho 3 

Guen Hana  Jetto ChiChi
2 tháng 12 2017 lúc 21:24

\(A=2^1+2^2+...+2^{2010}\)

\(A=\left(2^1+2^2\right)+\left(2^3+2^4\right)+\left(2^5+2^6\right)+...+\left(2^{2009}+2^{2010}\right)\)

\(A=2\left(1+2\right)+2^3\left(1+2\right)+2^5\left(1+2\right)+...+2^{2009}\left(1+2\right)\)

\(A=2.3+2^3.3+2^5.3+...+2^{2009}.3\)

\(A=3.\left(2+2^3+2^5+...+2^{2009}\right)\)\(⋮\)\(3\)

\(\Rightarrow A⋮3\)

\(A=\left(2^1+2^2+2^3\right)+\left(2^4+2^5+2^6\right)+\left(2^7+2^8+2^9\right)+...+\left(2^{2008}+2^{2009}+2^{2010}\right)\)

\(A=2\left(1+2+4\right)+2^4\left(1+2+4\right)+2^7\left(1+2+4\right)+...+2^{2008}\left(1+2+4\right)\)

\(A=2.7+2^4.7+2^7.7+...+2^{2008}.7\)

\(A=7.\left(2+2^4+2^7+...+2^{2008}\right)\)\(⋮\)\(7\)

\(\Rightarrow A⋮7\)

\(B=3^1+3^2+...+3^{2010}\)

\(B=\left(3^1+3^2\right)+\left(3^3+3^4\right)+\left(3^5+3^6\right)+...+\left(3^{2009}+3^{2010}\right)\)

\(B=3\left(1+3\right)+3^3\left(1+3\right)+3^5\left(1+3\right)+...+3^{2009}\left(1+3\right)\)

\(B=3.4+3.3^3+3.3^5+...+3^{2009}.4\)

\(B=4.\left(3+3^3+3^5+...+3^{2009}\right)\)\(⋮\)\(4\)

\(\Rightarrow B⋮4\)

\(B=3^1+3^2+...+3^{2010}\)

\(B=\left(3^1+3^2+3^3\right)+\left(3^4+3^5+3^6\right)+\left(3^7+3^8+3^9\right)+...+\left(3^{2008}+3^{2009}+3^{2010}\right)\)

\(B=3\left(1+3+3^2\right)+3^4\left(1+3+3^2\right)+3^7\left(1+3+3^2\right)+...+3^{2008}\left(1+3+3^2\right)\)

\(B=3.13+3^4.13+3^7.13+...+3^{2008}.13\)

\(B=13.\left(3+3^4+3^7+...+3^{2008}\right)\)\(⋮\)\(13\)

\(\Rightarrow B⋮13\)


Các câu hỏi tương tự
Phạm Minh Thư
Xem chi tiết
Time Lord
Xem chi tiết
Time Lord
Xem chi tiết
Time Lord
Xem chi tiết
Time Lord
Xem chi tiết
witch roses
Xem chi tiết
Đỗ Thiên Uy
Xem chi tiết
nguyễn phương thảo
Xem chi tiết
viet cute
Xem chi tiết