Các câu hỏi tương tự
cmr nếu \(\frac{a}{b}=\frac{c}{d}\)
thì: \(\frac{a^2+c^2}{b^2+d^2}=\frac{\left(a+c\right)^2}{\left(b+d\right)^2}\)(b+d khác 0)
CMR: nếu\(\frac{a}{b}=\frac{c}{d}thì\frac{a^2+b^2}{c^2+d^2}=\frac{ab}{cd}\)
CMR: Nếu \(\frac{a}{b}\)=\(\frac{b}{d}\)thì\(\frac{a^2+b^2}{b^2+d^2}\)=\(\frac{a}{d}\)
CMR nếu \(\frac{a^2+b^2}{c^2+d^2}=\frac{ab}{cd}\)(a,b,c,d khác 0). CMR \(\frac{a}{b}=\frac{c}{d}\)hoặc \(\frac{a}{b}=\frac{d}{c}\)
a) CMR: Nếu\(\frac{a}{b}=\frac{c}{d}\)thì\(\frac{a}{b}=\frac{a+c}{b+d}\)
b) Cho\(\frac{a+b}{a-b}=\frac{c+a}{c-a}\). CMR: a2 = bc
CMR nếu \(\frac{a}{b}=\frac{c}{d}\)thì \(\frac{a^2+b^2}{c^2+d^2}=\frac{a}{b}\)với b,c khác 0
Cmr nếu \(\frac{a}{b}=\frac{c}{d}\)thì \(\frac{a^2+b^2}{c^2+d^2}\)=\(\frac{ab}{cd}\)
CMR nếu \(\frac{a}{b}\)= \(\frac{b}{d}\)thì a2 + b2 / b2 + d2 = a / d
1. CM:
a) Nếu \(\frac{a+b}{a-b}=\frac{c+a}{c-a}\) thì \(a^2=bc\)
b) Nếu \(\frac{a}{b}=\frac{c}{d}\) thì \(\frac{\left(a+b\right)^2}{a^2-b^2}=\frac{\left(c+d\right)^2}{c^2-d^2}\)
c) Nếu \(\frac{a-c}{b-c}=\frac{b+c}{a+c}\)thì a=b