Ta có:
\(\frac{1}{x}+\frac{1}{y}+\frac{1}{z}=\frac{1}{x+y+z}\)
\(\Leftrightarrow\frac{1}{x}+\frac{1}{y}+\frac{1}{z}-\frac{1}{x+y+z}=0\)
\(\Leftrightarrow\frac{x+y}{xy}+\frac{x+y}{z\left(x+y+z\right)}=0\)
\(\Leftrightarrow\left(x+y\right)\left(\frac{1}{xy}+\frac{1}{z\left(x+y+z\right)}\right)=0\)
\(\Leftrightarrow\left(x+y\right)\cdot\frac{xy+z\left(x+y+z\right)}{xyz\left(x+y+z\right)}=0\)
\(\Leftrightarrow\left(x+y\right)\left(y+z\right)\left(z+x\right)=0\)
\(\Leftrightarrow x=-y\left(h\right)y=-z\left(h\right)z=-x\)
Xét \(x=-y\)
Ta có:
\(\frac{1}{x^{2017}}+\frac{1}{y^{2017}}+\frac{1}{z^{2017}}=\frac{1}{x^{2017}}+\frac{1}{-y^{2017}}+\frac{1}{y^{2017}}=\frac{1}{z^{2017}}\)
\(\frac{1}{x^{2017}+y^{2017}+z^{2017}}=\frac{1}{-x^{2017}+y^{2017}+z^{2017}}=\frac{1}{z^{2017}}\)
\(\Rightarrow\frac{1}{x^{2017}}+\frac{1}{y^{2017}}+\frac{1}{z^{2017}}=\frac{1}{x^{2017}+y^{2017}+z^{2017}}\left(dpcm\right)\)
Một cái chặt hơn nè:))
CMR nếu \(\frac{1}{x}+\frac{1}{y}+\frac{1}{z}=\frac{1}{x+y+z}\) thì \(\frac{1}{x^n}+\frac{1}{y^n}+\frac{1}{z^n}=\frac{1}{x^n+y^n+z^n}\) với n lẻ.
