A = (1/5)+(1/15)+(1/25)+...+(1/1985)=
1/5+1/3*5+1/5*5+1/7*5+.........+1/397*5
5A=1+1/3+1/5+1/7+.......+1/397
5A-1=1/3+1/5+1/7+.......+1/397
Đặt B= 1/3+1/5+1/7+.......+1/397
=>.......................Tính đc B=5,06241 (lấy gần bằng)=> A= 1,2124 (lấy số gần bằng)
=> A < 9/20
CMR : 1/5 + 1/15 + 1/25 +....+1/1985 <9/20
CMR:\(\frac{1}{5}+\frac{1}{15}+\frac{1}{25}+...+\frac{1}{1985}< \frac{9}{20}\)
CMR:
\(\frac{1}{5}+\frac{1}{15}+\frac{1}{25}+...+\frac{1}{1985}< \frac{9}{20}\)
CMR \(A=\frac{1}{5}+\frac{1}{15}+\frac{1}{25}+...+\frac{1}{1985}< \frac{9}{20}\)
CMR: \(\frac{1}{5}+\frac{1}{15}+\frac{1}{25}+...+\frac{1}{1985}<\frac{9}{20}\)
Cho : A= \(\frac{1}{5}+\frac{1}{15}+\frac{1}{25}+...+\frac{1}{1985}\)
CMR: A<\(\frac{9}{20}\)
Cm:1\5+1/15+1/25+...+1/1985<9/20
cm:1/5+1/15+1/25+....+1/1985<9/20
Chứng minh 1/5 + 1/15 + 1/25 +......+ 1/1985 < 9/20
