Question

CM: Đẳng thức \(\frac{2}{a.\left(a+1\right).\left(a+2\right)}=\frac{1}{a.\left(a+1\right)}+\frac{1}{\left(a+1\right).\left(a+2\right)}\)

Nhớ ghi cách làm lun nha !

Answer 1

Sửa đề : \(CM:\frac{2}{a\left(a+1\right)\left(a+2\right)}=\frac{1}{a\left(a+1\right)}-\frac{1}{\left(a+1\right)\left(a+2\right)}\)

Ta thấy : \(2=\left(a+2\right)-a\)

\(\Rightarrow VT=\frac{2}{a\left(a+1\right)\left(a+2\right)}=\frac{\left(a+2\right)-a}{a\left(a+1\right)\left(a+2\right)}\)

\(=\frac{a+2}{a\left(a+1\right)\left(a+2\right)}-\frac{a}{a\left(a+1\right)\left(a+2\right)}\)

\(=\frac{1}{a\left(a+1\right)}-\frac{1}{\left(a+1\right)\left(a+2\right)}=VP\)(đpcm)

Answer 2

sai đề rùi nha bạn

bên vế phải thì giữa hai phân số mình nghĩ phải là dấu trừ

Answer 3

\(\frac{2}{a\left(a+1\right)\left(a+2\right)}=\frac{1}{a\left(a+1\right)}-\frac{1}{\left(a+1\right)\left(a+2\right)}.\) Thì đúng hơn bạn ơi

\(\frac{1}{a\left(a+1\right)}-\frac{1}{\left(a+1\right)\left(a+2\right)}=\frac{a+2-a}{a\left(a+1\right)\left(a+2\right)}=\frac{2}{a\left(a+1\right)\left(a+2\right)}\)

Answer 4

uk nhầm