Question

\(C=\left(\dfrac{2}{9}-\dfrac{7}{12}\right).\dfrac{4}{3}+\left(\dfrac{16}{9}-\dfrac{5}{12}\right).\dfrac{4}{3}\)

Answer 1

`C = (2/9 - 7/12) * 4/3 + (16/9 - 5/12) * 4/3`

`C = [(2/9 - 7/12) + (16/9 - 5/12)] * 4/3`

`C = [ 2/9 - 7/12 + 16/9 - 5/12 ] * 4/3`

`C = [(2/9 + 16/9) - (7/12 + 5/12)] * 4/3`

`C = [2 - 1] * 4/3`

`C = 1 * 4/3`

`C = 4/3` 

Answer 2

\(C=\left(\dfrac{2}{9}-\dfrac{7}{12}\right).\dfrac{4}{3}+\left(\dfrac{16}{9}-\dfrac{5}{12}\right).\dfrac{4}{3}\\ C=\dfrac{4}{3}.\left(\dfrac{2}{9}-\dfrac{7}{12}+\dfrac{16}{9}-\dfrac{5}{12}\right)\\ C=\dfrac{4}{3}.\left[\left(\dfrac{2}{9}+\dfrac{16}{9}\right)-\left(\dfrac{7}{12}+\dfrac{5}{12}\right)\right]\\ C=\dfrac{4}{3}.\left(2-1\right)\\ C=\dfrac{4}{3}.1\\ C=\dfrac{4}{3}\)
Vậy \(C=\dfrac{4}{3}\)