a(b - c) + a(d + c)
= ab - ac + ad + ac
= ab + ad + (-ac + ac)
= ab + ad
= a.(b + d)
a(b - c) + a(d + c)
= ab - ac + ad + ac
= ab + ad + (-ac + ac)
= ab + ad
= a.(b + d)
a(b-c)+a(d+c)=a(b+d)
\(\Leftrightarrow\)ab-ac+ad+ac=a(b+d)
\(\Leftrightarrow\)a(b-c+d+c)=a(b+d)
\(\Leftrightarrow\)a(b+d)=a(b+d) (đpcm)
a(b-c)+a(d+c) = a(b+d)
phân tích vế trái ta có:
a(b-c) + a(d + c)
= ab - ac + ad + ac
= ab + ad
= a(b + d) = vế phải a( b + d)
vậy a(b-c) + a(d + c) = a(b + d)
a(b-c)+a(d+c)
=a(b-c+d+c)
=a(b+d-c-c)
=a(b+d) Vì c-c= 0
k cho mik nha