Ta có : \(\frac{1}{101}>\frac{1}{200}\)
\(\frac{1}{102}>\frac{1}{200}\)
\(...>\frac{1}{200}\)
Mà \(\frac{1}{200}=\frac{1}{200}\)
Suy ra : \(\frac{1}{101}+\frac{1}{102}+...+\frac{1}{200}>\frac{1}{200}+\frac{1}{200}+...+\frac{1}{200}\)
Mời nhân tài giải nốt.
Chứng tỏ :
\(1-\frac{1}{2}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{199}-\frac{1}{200}=\frac{1}{101}+\frac{1}{102}+...+\frac{1}{200}\)
Chứng tỏ:
\(\frac{1}{101}+\frac{1}{102}+\frac{1}{103}+...+\frac{1}{199}+\frac{1}{200}\) < 1
\(\text{Chứng tỏ:}\)
\(1-\frac{1}{2}+\frac{1}{3}-\frac{1}{4}+.....+\frac{1}{199}-\frac{1}{200}=\frac{1}{101}+\frac{1}{102}+.....+\frac{1}{200}\)
A=\(\frac{1}{101}+\frac{1}{102}+............+\frac{1}{199}+\frac{1}{200}\)
Chứng tỏ A<\(\frac{5}{6}\)
chứng minh rằng
\(A=\frac{1}{101}+\frac{1}{102}+....+\frac{1}{199}+\frac{1}{200}< 1\)1
Chứng minh rằng :
\(\frac{1}{101}+\frac{1}{102}+....+\frac{1}{199}+\frac{1}{200}<1\)
Chứng minh :
\(1-\frac{1}{2}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{199}-\frac{1}{200}=\frac{1}{101}+\frac{1}{102}+...+\frac{1}{200}\)
chung minh rang
\(1-\frac{1}{2}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{199}-\frac{1}{200}=\frac{1}{101}+\frac{1}{102}+\frac{1}{103}+...+\frac{1}{200}\)
giup minh minh like cho nho giai chi tiet mot chut nhe
Cho \(A=\frac{1}{101}+\frac{1}{102}+\frac{1}{103}+\frac{1}{104}+......+\frac{1}{199}+\frac{1}{200}\)
Chứng tỏ \(A
