\(\frac{M}{3}=\frac{1}{3^2}+\frac{1}{3^3}+\frac{1}{3^4}+...+\frac{1}{3^{100}}\)
\(\frac{2M}{3}=M-\frac{M}{3}=\frac{1}{3}-\frac{1}{3^{100}}\)
\(2M=1-\frac{1}{3^{99}}\Rightarrow M=\frac{1}{2}-\frac{1}{2.3^{99}}
\(\frac{M}{3}=\frac{1}{3^2}+\frac{1}{3^3}+\frac{1}{3^4}+...+\frac{1}{3^{100}}\)
\(\frac{2M}{3}=M-\frac{M}{3}=\frac{1}{3}-\frac{1}{3^{100}}\)
\(2M=1-\frac{1}{3^{99}}\Rightarrow M=\frac{1}{2}-\frac{1}{2.3^{99}}
chứng tỏ rằng : M=1/3+1/3^2+1/3^3+......+1/3^99 <1/2
A) Tính M: 3/4.8/9.15/16.9999/10000 B) Chứng tỏ rằng: 1/26+1/27+...+1/50=99/50-97/49+...+7/4-5/3+3/2-1
chứng minh rằng M=1/3+1/3^2+1/3^3+......+1/3^99 < 1/2
A=1*2-1/2! + 2*3-1/3! +....+ 99*100-1/100!
Chứng tỏ rằng A<1
Cho A= 1/4+1/4^2+1/4^3+...+1/4^99. Chứng tỏ rằng A<1/3
chứng minh : M=1/3+1/32+1/33+.....+1/399
Chứng minh rằng : M<1/2
Bạn nào giúp mk vs
chứng tỏ rằng:M=1/3+1/3^2+1/3^3+....+1/3^99 <1/2
Chứng tỏ rằng
1/2!+2/3!+3/4!+.....+99/100!<1
Giúp mìh vs
Chứng tỏ rằng: 1-1/2+1/3-1/4+...+1/99-1/200=1/101+1/102+...+1/199+1/200