Question

Chứng tỏ rằng :

a) \(\frac{1717}{2929}\)=\(\frac{171717}{292929}\)

b) \(\frac{3210-34}{4170-41}\)=\(\frac{6420-68}{8340-82}\)

Answer 1

a) \(\frac{1717}{2929}=\frac{17.101}{29.101}=\frac{17}{29}\)

\(\frac{171717}{292929}=\frac{17.10101}{29.10101}=\frac{17}{29}\)

=> \(\frac{1717}{2929}=\frac{171717}{292929}\left(=\frac{17}{29}\right)\)

Answer 2

b) \(\frac{6420-68}{8340-82}=\frac{2\left(3210-34\right)}{2\left(4170-41\right)}=\frac{3210-34}{4170-41}\)

Vậy; \(\frac{3210-34}{4170-41}=\frac{6420-68}{8340-82}\)