Theo đề bài ta có:
A = \(1+2+2^2+2^3+...+2^{11}\)
\(\Rightarrow A=2^0+2^1+2^2+2^3+...+2^{11}\)
\(\Leftrightarrow A=2^0.\left(1+2+2^2+2^3+2^4+2^5\right)+2^6.\left(1+2+2^2+2^3+2^4+2^5\right)\)
\(\Rightarrow A=2^0.63+2^6.63\)
\(\Rightarrow A=63.\left(2^0+2^6\right)\)
\(\Rightarrow A=63.65\)
Vậy A chia hết cho 13 ( vì 65 chia hết cho 13)