Question

Chứng minh

a)\(\frac{1}{2}\)<\(\frac{1}{51}\)+\(\frac{1}{52}\)+...+\(\frac{1}{100}\)<1

b)\(\frac{7}{12}\)<\(\frac{1}{21}\)+\(\frac{1}{22}\)+...+\(\frac{1}{40}\)<\(\frac{5}{6}\)

Giúp mk với

Answer 1

a) \(\frac{1}{2}< \frac{1}{51}+\frac{1}{52}+...+\frac{1}{100}< 1\)

\(\frac{1}{51}+\frac{1}{52}+...+\frac{1}{100}=\left(\frac{1}{51}+\frac{1}{52}+...+\frac{1}{60}\right)+\left(\frac{1}{61}+\frac{1}{62}+...+\frac{1}{70}\right)+...+\left(\frac{1}{91}+\frac{1}{92}+...+\frac{1}{100}\right)\)\(\frac{1}{60}\cdot10< \frac{1}{51}+\frac{1}{52}+...+\frac{1}{60}< \frac{1}{50}\cdot10\)

\(\frac{1}{6}< \frac{1}{51}+\frac{1}{52}+...+\frac{1}{60}< \frac{1}{5}\)(1)

\(\frac{1}{70}\cdot10< \frac{1}{61}+\frac{1}{62}+...+\frac{1}{70}< \frac{1}{60}\cdot10\)

\(\frac{1}{7}< \frac{1}{61}+\frac{1}{62}+...+\frac{1}{70}< \frac{1}{6}\)(2)

.... (tương tự )

\(\frac{1}{100}\cdot10< \frac{1}{91}+\frac{1}{92}+...+\frac{1}{100}< \frac{1}{90}\cdot10\)

\(\frac{1}{10}< \frac{1}{91}+...+\frac{1}{100}< \frac{1}{9}\)

Answer 2

Từ (1)(2)(3)(4) và (5)

\(\frac{1}{6}+\frac{1}{7}+\frac{1}{8}+\frac{1}{9}+\frac{1}{10}< \frac{1}{51}+\frac{1}{52}+...+\frac{1}{100}< \frac{1}{5}+\frac{1}{6}+\frac{1}{7}+\frac{1}{8}+\frac{1}{9}\)

\(\frac{1}{2}< \frac{1624}{2520}< \frac{1}{51}+...+\frac{1}{100}\)

\(1>\frac{1879}{2520}>\frac{1}{51}+...+\frac{1}{100}\)