C = 2 + 22 + 23 + ... + 299 + 2100
= (2 + 22 + 23 + 24 + 25) + ... + ( 296 + 297 + 298 + 299 + 2100)
= 62 + ... + 295.( 2 + 22 + 23 + 24 + 25)
= 62 + ... + 295 . 62
= 62 . (1 + 295) chia hết cho 31
kudo shinichi khong dua ra ket qua ro rang
C = 2 + 22 + 23 + ... + 299 + 2100
= (2 + 22 + 23 + 24 + 25) + ... + ( 296 + 297 + 298 + 299 + 2100)
= 62 + ... + 295.( 2 + 22 + 23 + 24 + 25)
= 62 + ... + 295 . 62
= 62 . (1 + 295) chia hết cho 31
kudo shinichi khong dua ra ket qua ro rang
chung minh rang:S=2+2^2+2^3+....+2^99+2^100 chia het cho 31
chung minh rang s=2+22+23...+299+2100 chia het cho 31
chung to tong sau chia het cho 31
S=2+22+23+....+299+2100.
NHANH nhe minh dang can gap
cau 1. Chung minh rang C=2+2^2+2^3+....+2^99+2^100 chia het cho 31
b, Tinh tong C
c,Tim x de 2^2x-1-2=C
CAC BAN GIUP MINH BAIF NAY VOI
chứng minh ý a 8mu10 cong 2 mũ 20 chia hết cho41
chứng minh ý b 31 mu36 nhận 36 -313 mu 5 nhận 299 chia hết ch
chung minhý c 3 mu n công 3 cộng 2 mu n công 3 công 2 mu n công 2 công 2 mu n công 2 chia hết 6
chung minh y d d=2 cong 2 mu 2 cong 2mu 3 cong 2 mu 4 cong 2 mu 5 cong 2 mu 6 cong ....cong 2 mu 58 cong 2 mu 59 cong 2 mu 60 chia het cho 31
chung minh y e, e= 1cong 3 cong 3 mu 2 cong 3 mu 3 cong..cong 3 mu 98 cong 3 mu 99 chung minh e chia het cho5 chia het cho11
cho B =1+2+2^2+2^3+.....+2^100.Chung to rang:a)B khong chia het cho 3
b)B khong chia het cho 31
chung minh rang A=21+22+23+...+299+2100 chia het cho 6
Chung to
A=2+21+22+23+...+210
A chia het cho 3, A chia het cho 31
b)A=2+22+23+24+2100
A chia het cho 31, A chia het cho 5
CHUNG MINH RANG:
a/ S1 = 5 + 52 + 53+......+ 52004 chia het cho 6 ; 31 ; 156
b/ S2= 2+ 22 + 23 + ......+ 2100 chia het cho 31
c/ S3 = 165 + 215 chia het cho 33