Tìm x
1/(6x-32).35=5.37
2/8x-5.23=(5.2)3-53.23
chứng tỏ số abcabc là bội cuar7,11 và 13
tìm x biết:
a) x+17=-33
b)2-(x-5)=5.2^3
c)1009.x=(-1)+2+(-3)+4+(-5)+6...9+(-2017)+2018
tìm x;y thuộc z:
a) 1</x-2/<4
b) 3^/x/+1=5.2^4+2016^0
c) /x+2/+/y-4/=0
-2/3.(x-4)=1/3.(2x-1)
1/5.2x+1/3.2x+1=1/5.27+1/3.28
3^2 . ( x + 4 ) - 5^2 = 5.2^2
Tính hợp lý:
a) A=\(2021^2\)-2020.(2021+1)
b) B=1+2-3-4+5+6-7-8+9+10-...+2018-2019-2020+2021
c) C=\(\dfrac{5.4^{15}.9^9-4.3^{20}.8^9}{5.2^9.6^{19}-7.2^{29}.27^6}\)
Tìm x biết :1)-2/3(x-1/4)=1/3(2x-1)
2)1/5.2x+1/3.2x+1=1/5.2x+1+1/3.28
[130-3.(5.2-5.2)]:2
1/5.2^x+1/3.2x+1=1/5.2^7+1/3.2^8