Question

 chứng minh rằng các tổng, các hiệu sau chia hết cho 10 

a, 481^n + 1999^1999

 b, 16^2001 - 8^2000 

c, 19^2005 + 11^2004 

d, 17^5 + 24^4 - 13^21

Giúp mình nhé !

Answer 1

= ( ...1 ) + (1999²)⁹⁹⁹ · 1999

= (...1) + (...1)⁹⁹⁹ · 1999

= (...1 ) + (...1) · 1999

= (...1 ) + (...1999)

=(...2000 ) \(⋮10\)

b) 16²⁰⁰¹ - 8²⁰⁰⁰

= ( ... 6 )²⁰⁰¹ - ( 8² )¹⁰⁰⁰

= (...6) - (...6)¹⁰⁰⁰

=(...6 ) - (...6 )

= ( ...0 ) \(⋮10\)

c) 19²⁰⁰⁵ + 11²⁰⁰⁴

= ( 19² )¹⁰⁰² · 19 + (...1 )²⁰⁰⁴

= ( ... 1 )¹⁰⁰² · 19 + (...1)

= ( ...1 ) · 19 + (...1 )

= (...19 ) + (...1)

=( ... 20 ) \(⋮10\)

d) 17⁵ + 24⁴ - 13²¹

= (...7⁴) · 17 + (..4² )² - ( ...3⁴ )⁵ · 13

= (...1) · 17 + ( ...6 )² - ( ...1)⁵ · 13

= ( ...17 ) + (...6 ) - (...1) · 13

= (...23 ) - (..13)

= (...10 )\(⋮10\)

Answer 2

câu a) https://olm.vn/hoi-dap/question/228404.html

câu b)hhttps://olm.vn/hoi-dap/question/228404.html

c)https://olm.vn/hoi-dap/question/721614.html

d)https://olm.vn/hoi-dap/question/721614.html