a) Ta có:171205=(174)301+1=(...1)301.171=(...1).(...7)=(...7)
Mà (...7)-2=(..5) chia hết cho 5
=>171205-2 chia hết cho 5
b) Ta có : 321381=(324)345+1=(...6)345.321=(...6).(...2)=(...2)
Mà (...2)+3=(...5) chia hết cho 5
=>321381+3 chia hết cho 5
ta có:
\(17^{1205}=\left(17^4\right)^{301+1}=\left(...1\right)^{103}.17^1=\left(...1\right).\left(...7\right)=\left(...7\right)\)
mà:
\(\left(...7\right)-2=\left(...5\right)⋮5\)
\(\Rightarrow17^{1205}-2⋮5\)
bn học tốt