giả sử a \(\ge\)b \(\Rightarrow\)a = b + m ( m \(\ge\)0 )
do đó : \(\frac{a}{b}+\frac{b}{a}=\frac{b+m}{b}+\frac{b}{b+m}\)
\(=1+\frac{m}{b}+\frac{b}{b+m}\ge1+\frac{m}{b+m}+\frac{b}{b+m}=1+\frac{m+b}{b+m}=2\)
Vậy \(\frac{a}{b}+\frac{b}{a}\ge2\)( a,b thuộc N* )
Dấu " = " xảy ra khi a = b