Ta có : ab x 101 = ab x ( 100 +1 ) = ab x 100 + ab = ab00 + ab = abab
vậy abab + ab = 101
Ta có:\(abab:ab=101\)
\(\Rightarrow ab.101:ab=101\)
\(\Rightarrow101=101\)
abab : ab
= ab00 + ab : ab
= ab ( 100 + 1 ) : ab
= 101ab : ab
= 101 ( đpcm )
\(\overline{abab}:\overline{ab}=101\)
\(\overline{abab}=\overline{ab00}+\overline{ab}\)
\(\Rightarrow\overline{abab}=\overline{ab}.100+\overline{ab}=\overline{ab}.101\)
Học tốt @-@
abab : ab = 101
vì ab nhân101=abab
abab = ab . 100 + ab
suy ra abab = ab . 100 + ab = ab . 100
ta có: abab : ab
= ab.101 : ab
= 101 . (ab:ab)
= 101.1 = 101
Ta có: abab:ab=101
<=> (ab00+ab):ab=101
<=> ab00:ab+ab:ab=101
<=> 100+1 =101.
Vậy abab:ab=101.
abab:ab=101
=(ab00+ab):ab
=ab00:ab+ab:ab
=100+1
=101
