-3x2 + 6x -y2 +6y -12
<=> (-3x2 +6x -3) +( -y2 + 6y - 9)
<=> -3(x2 -2x +1) - (y2 -6y +9)
<=> -3(x-1)2 - (y-3)2
mà -3(x-1)2>=0
-(y-3)2>=0
=> dpcm
= -3(x^2-2x+1)-(y^2-6y+9)
=-3(x-2)^2-(y-3)^2 nhỏ hơn hoặc bằng 0
-3x2 + 6x -y2 +6y -12
<=> (-3x2 +6x -3) +( -y2 + 6y - 9)
<=> -3(x2 -2x +1) - (y2 -6y +9)
<=> -3(x-1)2 - (y-3)2
mà -3(x-1)2>=0
-(y-3)2>=0
=> dpcm
= -3(x^2-2x+1)-(y^2-6y+9)
=-3(x-2)^2-(y-3)^2 nhỏ hơn hoặc bằng 0
Cho tam giac ABC can tai B ke BH vuong goc AC ( H thuoc AC )
a) Chung minh: HA = HC
b) Ke HD vuong goc AB ( D thuoc AB ), HE vuong goc BC ( E thuoc BC ). Chung minh: HD = HE
c) Chung minh: tam giac BDE can
d) Chung minh: \(BE^2+DH^2=BC^2-HA^2\)
MINH DANG CAN GAP NHO CAC BAN GIUP CHO ( phan a, b, c cac ban co the lam hoac ko thi tuy nhung nho cac ban giup minh phan d )
CAM ON CAC BAN NHIEU
Tim x, y, z biet
a ) |x-3,5|+ |x+5|=0
b) |x-1| + (y+1)^2 + |z-1|=0
c) ( x-1/3)^2 + (y-2)^2+ (z-1)^2 be hon hoac bang 0
d)(x-z)^2+ (y+x)^2 + (z+1/4)^2 =0
Cac ban giup minh voi minh can gap lam
Cac ban oi giup minh voi
tim x biet 6.4/x=x/99tim cac so nguyen biet (|x|-3)(x^2+4) be hon hoac bang 4hai dia diem a va b cach nhau 90kmhai nguoi di xe dap cung mot luc tu ava bde gap nhau va ho gap nhau cach a 50km;nhung neu nguoi di tu b di nhanh hon xuat phat truoc nguoi a 1 gio thi ho gap nhau cach a 350/9km tinh van toc moi nguoiCac giai ho minh voi minh se tick cho
Cac ban nho viet ho cach lam min voi
tim cac so nguyen tu -căn 49 đến căn 25 chia hết cho 2
cac ban lam nhanh giup minh minh dang can gap nhe
Cho tam giac ABC can tai A. Phan giac AM \(\left(M\in BC\right)\), co AB = 5cm, BC = 6cm
a) Chung minh: tam giac AMB = tam giac AMC
b) Chung minh: Am vuong goc BC
c) Tinh AM
d) Qua B ve duong thang a vuong goc voi AC va cat AM tai H. Chung minh: CH vuong goc AB
MINH DANG CAN RAT RAT GAP NHO CAC BAN GIAI GIUM CHO MINH ( cac ban muon giai phan a, b, c ko thi tuy nhung nho cac ban giup minh phan d voi )
CAM ON CAC BAN NHIEU
x/27=-2/3,6 cac ban oi hay giup minh gium nhe minh dang can gap
cho bz - cy /a = cx - az /b = ay - bx /c
chung minh rang x/a = y/b = z/c
MAY BAN LM GAP BAI NAY GIUM MIK TRC NHE! GIAI RO RANG CHI TIET RA NHE.MIK CAN GAP
cho ham so \(y=f\left(x\right)=ax^2+bx+c\)(a;b;c thuoc Q)
chung to rang f(-2)*f(3) nho hon hoac bang 0, biet rang 13a+b+2c=0
Tim GTNN cua bt sau
a, lx-2l + l x+28l + lx-60l
b, lxl + lx-1l + lx-2l+...+lx-2004l
Cac ban giai chi tiet giup minh nhe, minh dang can gap.