Question

Chứng minh rằng: 27^10+3^29+9^14 chia hết cho 13

 

Answer 1

\(27^{10}+3^{29}+9^{14}=3^{30}+3^{29}+3^{28}=3^{28}\cdot\left(3^2+3+1\right)=3^{28}\cdot13\)chia hết cho 13

Answer 2

\(27^{10}+3^{29}+9^{14}\)

\(=\left(3^3\right)^{10}+3^{29}+\left(3^2\right)^{14}\)

\(=3^{30}+3^{29}+3^{28}\)

\(=3^{28}.\left(3^2+3+1\right)\)

\(=3^{28}.\left(9+3+1\right)\)

\(=3^{28}.13\)chia hết cho 13

=> đpcm

Ủng hộ mk nha ^_-