Các câu hỏi tương tự
chung minh : 1/5^3+1/6^3+1/7^3+........+1/2004^3 <1/40
chung minh : 1/5^3+1/6^3+1/7^3+.........+1/2004^3 < 1/40
Chứng minh rằng : 1/65 < 1/5^3 + 1/6^3 + 1/7^3 + ... + 1/2004^3 <1/40
chứng minh rằng
\(\frac{1}{5^3}+\frac{1}{6^3}+\frac{1}{7^3}+...+\frac{1}{2004^3}\)<\(\frac{1}{40}\)
chung minh rang:1/(1*2)+1/(3*4)+1/(5*6)+.....+1/(49*50)=1/26+1/27+1/28+....+1/50
cho a=1=1\2+1\3-1\4+1\5...+1\49-1\50.Chung to rang 7\12<4<5\6
1/5^3+1/6^3+...+1/2004^3<1/40
chứng minh rằng \(\frac{1}{65}\)<\(\frac{1}{5^3}+\frac{1}{6^3}+...+\frac{1}{2004^3}\)<\(\frac{1}{40}\)
chung minh rang
A = 1/5+1/5^2+1/5^3+...+1/5^2008<1/4