Question

chứng minh rằng: 1-1/2+1/3-1/4+.......+1/199-1/200=1/101+1/102+1/103+.......+1/200

Answer 1

Lời giải:

$1-\frac{1}{2}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{199}-\frac{1}{200}$

$=(1+\frac{1}{3}+\frac{1}{5}+...+\frac{1}{199})-(\frac{1}{2}+\frac{1}{4}+...+\frac{1}{200})$

$=(1+\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+>..+\frac{1}{199}+\frac{1}{200})-2(\frac{1}{2}+\frac{1}{4}+...+\frac{1}{200})$

$=(1+\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+....+\frac{1}{199}+\frac{1}{200})-(1+\frac{1}{2}+\frac{1}{3}+...+\frac{1}{100})$

$=\frac{1}{101}+\frac{1}{102}+...+\frac{1}{200}$