\(\left(64.27\right)^6=12^{18}\Leftrightarrow1728^6=12^8\)
Ta có :
\(12^{18}=\left(12^3\right)^6=1728^6\)
Vì \(1728^6=1728^6\)
\(\Leftrightarrow\left(64.27\right)^6=12^{18}\) đó là điều mà ta phải chứng minh
Chứng minh (64.27) mũ 6= 12 mũ 18
chứng minh \(\left(64.27\right)^6.75^{18}=30^{36}\)
Tìm Min hoặc Max:
A = \(\dfrac{2015}{18+12\left|x-6\right|}\)
B = \(\left|x+\dfrac{1}{3}\right|+\left|x-1\right|\)
Thục hiện phép tính
a) A = \(\frac{5.\left(2^2.3^2\right)^9.\left(2^2\right)^6-2.\left(2^2.3\right)^{14}.3^4}{5.2^{28}.3^{18}-7.2^{29}.3^{18}}\)
b) B = \(81.\left(\frac{12-\frac{12}{7}-\frac{12}{289}-\frac{12}{85}}{4-\frac{4}{7}-\frac{4}{289}-\frac{4}{85}}:\frac{5+\frac{5}{13}+\frac{5}{169}+\frac{5}{91}}{6+\frac{6}{13}+\frac{6}{169}+\frac{6}{91}}\right).\frac{158158158}{711711711}\)
Cho \(6\left(x+y\right)=3\left(y+z\right)=5\left(x+z\right)\)
Chứng minh \(\frac{z-y}{3}=\frac{y-x}{12}\)
\(15\dfrac{5}{6}+\left(\dfrac{17}{18}-\dfrac{5}{12}\right):3\dfrac{1}{6}\)
tính
Chứng minh rằng:
a)\(12^8.9^{12}=18^{16}\)
b)\(\frac{\left(5^4-5^3\right)^3}{125^5}=\frac{64}{25^5}\)
c)\(\frac{9^3}{\left(3^4-3^3\right)^2}=\frac{1}{4}\)
Làm nhanh giúp mình nhá. Thanks. ^_^
Tính nhanh
\(6\left(\frac{-2}{3}\right)+12\left(\frac{-2}{3}\right)^2+18\left(\frac{-2}{3}\right)^3\)
\(\dfrac{15}{12}+\dfrac{5}{13}-\dfrac{3}{12}-\dfrac{18}{13}-\dfrac{1}{3}\)
\(14.\dfrac{3}{2}+\dfrac{6}{5}:\left(\dfrac{-2}{5}\right)\)
\(\sqrt{\dfrac{1}{4}+\dfrac{2}{3}-\left(\dfrac{1}{3}\right)^2}\)
