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chung minh rang: 1/5+1/15+1/25+....+1/1985<9/20
Chứng minh rằng:
1/5+1/15+1/25+.....+1/1985 < 9/4
Chứng minh rằng : \(\frac{1}{5}+\frac{1}{15}+\frac{1}{25}+....+\frac{1}{1985}< \frac{9}{20}\)
CMR:
1/5 +1/15 +1/25 +...+1/1985 < 9/20
CMR \(\frac{1}{5}+\frac{1}{15}+\frac{1}{25}\) +..................+\(\frac{1}{1985}<\frac{9}{20}\)
bài 1 : tính hợp lý
a -(30+15-21)-(30+15+9) c 27.19+31.27
b 6-5+4-20+21-18 d (-25).64+36.(-25) e 18.36+72.15
Chứng minh
\(\frac{1}{5}+\frac{1}{15}+\frac{1}{25}+........+\frac{1}{1785}>\frac{9}{20}\)
Chứng minh rằng:frac{1}{5}+frac{1}{15}+frac{1}{25}+....+frac{1}{1985} frac{9}{20}mk làm thế này đúng ko mọi ngườiĐặt Afrac{1}{3}+frac{1}{5}+frac{1}{7}+frac{1}{9}+......+frac{1}{243}Afrac{1}{3}+left(frac{1}{5}+frac{1}{7}+frac{1}{9}right)+left(frac{1}{11}+frac{1}{13}+frac{1}{15}+....+frac{1}{27}right)+left(frac{1}{29}+frac{1}{31}+frac{1}{33}+....+frac{1}{81}right)+left(frac{1}{83}+frac{1}{85}+frac{1}{87}+.....+frac{1}{243}right)Afrac{1}{3}+frac{1}{9}.3+frac{1}{27}.9+frac{1}{81}.27+frac{1}{243}.81f...
Đọc tiếp
Chứng minh rằng:\(\frac{1}{5}+\frac{1}{15}+\frac{1}{25}+....+\frac{1}{1985}< \frac{9}{20}\)
mk làm thế này đúng ko mọi người
Đặt \(A=\frac{1}{3}+\frac{1}{5}+\frac{1}{7}+\frac{1}{9}+......+\frac{1}{243}\)
\(A=\frac{1}{3}+\left(\frac{1}{5}+\frac{1}{7}+\frac{1}{9}\right)+\left(\frac{1}{11}+\frac{1}{13}+\frac{1}{15}+....+\frac{1}{27}\right)+\left(\frac{1}{29}+\frac{1}{31}+\frac{1}{33}+....+\frac{1}{81}\right)+\left(\frac{1}{83}+\frac{1}{85}+\frac{1}{87}+.....+\frac{1}{243}\right)\)
\(=>A>\frac{1}{3}+\frac{1}{9}.3+\frac{1}{27}.9+\frac{1}{81}.27+\frac{1}{243}.81=\frac{1}{3.5}=\frac{5}{3}\)
\(=>A>\frac{5}{3}>\frac{5}{4}=>A< \frac{5}{4}\)
\(=>\frac{1}{3}+\frac{1}{5}+\frac{1}{7}+....+\frac{1}{397}< \frac{5}{4}\)
\(=>1+\frac{1}{3}+\frac{1}{7}+....+\frac{1}{397}< \frac{5}{4}\)
\(=>\frac{1}{5}.\left(1+\frac{1}{3}+\frac{1}{5}+\frac{1}{7}+....+\frac{1}{397}\right)< \frac{9}{4}.\frac{1}{5}\)
\(=>\frac{1}{5}+\frac{1}{15}+\frac{1}{25}+......+\frac{1}{1985}< \frac{9}{20}\)
CMR: \(\frac{1}{5}+\frac{1}{13}+\frac{1}{25}+...+\frac{1}{1985}<\frac{9}{20}\)