Ta có : 8102= 8100.. 82 = ( ....6 ) .(...4) = .....4
2102 = 2100 . 22 = ( ....6 ). 4 = ...4
8102 - 2102 = ....4 - ...4 = ...0 => đpcm
Vậy 8102 - 2102 chia hết cho 10
hok tốt
\(8^{102}-2^{102}=8^{25\times4+2}-2^{25\times4+2}\)
\(=8^{25\times4}\times8^2-2^{25\times4}\times2^2\)
\(=\left(...6\right)\times64-\left(...6\right)\times4\)
\(=\left(...4\right)-\left(...4\right)=\left(...0\right)⋮10\)