ta có: \(\frac{1}{3^2}< \frac{1}{2.3};\frac{1}{4^2}< \frac{1}{3.4};...;\frac{1}{2015^2}< \frac{1}{2014.2015};\frac{1}{2016^2}< \frac{1}{2015.1026};\frac{1}{2017^2}< \frac{1}{2016.2017}\)
=> 1/22 + 1/32 + 1/42 + ... + 1/20152 + 1/20162 + 1/20172 < 1/22 + (1/2.3 + 1/3.4 + ....+1/2014.2015 + 1/2015.2016 + 1/2016.2017)
= 1/4 + 1/2 - 1/2017 = 3/4- 1/2017 < 3/4
=> đ p c m
ta có: \(\frac{1}{3^2}< \frac{1}{2.3};\frac{1}{4^2}< \frac{1}{3.4};...;\frac{1}{2015^2}< \frac{1}{2014.2015};\frac{1}{2016^2}< \frac{1}{2015.1026};\frac{1}{2017^2}< \frac{1}{2016.2017}\)
=> 1/22 + 1/32 + 1/42 + ... + 1/20152 + 1/20162 + 1/20172 < 1/22 + (1/2.3 + 1/3.4 + ....+1/2014.2015 + 1/2015.2016 + 1/2016.2017)
= 1/4 + 1/2 - 1/2017 = 3/4- 1/2017 < 3/4
=> đ p c m
