Cho da thuc 4x^5-3x^3+7x^3y+ax^5y (a la hang). Biet rang bac cua don thuc nay bang 4. Tim a
a,tim a biet da thuc A(x)=ax2- 1/2x +1 co 1 nghiem la -1/2
b, tim a,b cua da thuc :B(x)= ax2+bx+5 biet B(1)=6 va B(-2) = 15
c, cho da thuc C(x)= ax+b .Tim a,b biet :
x=4 la nhgiem cua C(x)va C(2)=1
tim x biet:
a) (4x-3)^4=(4x-3)^2
b) co hay khong so huu ti thoa man?
(2x+3)^2+(3x-2)^4=0
YOU DO FAST. THANKS
Cho da thuc : P =\(ax^4y^3+10xy^2+4y^3-2x^4y^3-3xy^2+bx^3y^4\)
Biet rang a ; b la hang so va da thuc P co bac 3, hay tinh a, b
Tim x biet: (3/4x+5)-(2/3x-4)-(1/6x+1)=(1/3+4)-(1/3x-3)
Cho đa thức P(x)=ax4-6x3+7-2x+3x2-4x4
Tìm a biết đa thức P(x) có bậc là 3
Tim x biet:
(3/4x + 5) - (2/3x - 4) - (1/6x + 1) = (1/3x + 4) - (1/3x - 3)
tim x biet :
a) ( 2x^2+4 ) - (x^2-3/2 ) = (-3+4x^2)+ ( -4x^2/3+1)
b) ( I xI -4) - ( 2- I-xI ) = 1/3 . I xI -5
xac dinh a,b,c biet rang:
2x^2-3x-4=ax^2+bx-(c+1)
ax^3+5x^2-4x+2=4x^3-(b-2)x^2+cx+(d-3)