Question

\(ChoM\left(x\right)=4x^3+x^2-7x+3x^2-x^3+9\)

         \(N\left(x\right)=6+5x^3+6x^2+3x-2x^2-2x^3\)

THU GỌN ĐA THỨC M(x),N(x)

Answer 1

\(M\left(x\right)=4x^3+x^2-7x+3x^2-x^3+9\)

=\(\left(4x^3-x^3\right)+\left(x^2+3x^2\right)-7x+9\)

=\(3x^3+4x^2-7x+9\)

\(N\left(x\right)=6+5x^3+6x^2+3x-2x^2-2x^3\)

=\(\left(5x^3-2x^3\right)+\left(6x^2-2x^2\right)+3x+6\)

=\(3x^3+4x^2+3x+6\)

Answer 2

\(M\left(x\right)=3.x^3+4x^2-7x+9\)

\(N\left(x\right)=3.x^3+4.x^2+3x+6\)

Answer 3

M(x)=4x³+x²-7x-3x²+x^3-9=5x³-2x²-7x-9

N(x)=6+5x³+6x²+3x-2x²-2x³⁼3x³+4x²+3x+6